SOLUTION: hi....so i really need help i just cant understan direct joint and inverse variations....so ok here is the problem.
Q: if y varies directly as x and y=9 when x=6, find y when
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-> SOLUTION: hi....so i really need help i just cant understan direct joint and inverse variations....so ok here is the problem.
Q: if y varies directly as x and y=9 when x=6, find y when
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Question 125728: hi....so i really need help i just cant understan direct joint and inverse variations....so ok here is the problem.
Q: if y varies directly as x and y=9 when x=6, find y when x=8 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! if y varies directly as x and y=9 when x=6, find y when x=8
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If y varies directly as x, y = kx
You 1st need to solve for "k":
9 = k*6
k= 3/2
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So the proper equation for your problem is
y = (3/2)x
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Then, if x = 8 you can solve for "y":
y = (3/2)*8 = 12
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Comment:
If you have indirect variation y = k/x
Joint is the same as direct
inverse is the same as indirect
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Cheers,
Stan H.
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