SOLUTION: One number is 12 more than another. The sum of the smaller number and twice the larger number is 36. Find the larger number

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Question 125707: One number is 12 more than another. The sum of the smaller number and twice the larger number is 36. Find the larger number
Found 2 solutions by solver91311, MathLover1:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
One number is x, so the "another" number has to be x - 12.

Twice the larger number is 2x. The sum of the smaller number (x - 12) and twice the larger number (2x) is (meaning equals) 36.

So, 2x%2B%28x-12%29=36

3x-12=36

3x=48

x=16. The larger number is 16.

Check: The smaller number has to be 4, 2 times 16 is 32 plus 4 is 36. Answer checks.

Choose x to be the smaller number and work it out. See if you get the same result. (If you don't, keep trying)

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

One number (x) is 12 more than another (y):
x+=+y+%2B+12
x is the larger number
y is the smaller number
so, we have
y+%2B+2x+=+36 .....substitute x
y+%2B+2%28y+%2B+12%29+=+36
y+%2B+2y+%2B+24+=+36
3y+=+36+-24
3y+=+12
y+=+4

then
x+=+y+%2B+12
x+=+4+%2B+12
x+=+16
check:
y+%2B+2x+=+36
4%2B+2%2A16+=+36
4%2B+32=+36
36+=+36