SOLUTION: what is the equation of a horizontal line that passes through the point at (-2,-3)???? I do not understand this question could someone please help? thank u

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Question 125495: what is the equation of a horizontal line that passes through the point at
(-2,-3)????
I do not understand this question could someone please help? thank u

Found 2 solutions by Edwin McCravy, solver91311:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
what is the equation of a horizontal line that passes through the point at
(-2,-3)????
I do not understand this question could someone please help? thank u
Let's draw the point (-2,-3):



Now draw a horizontal line through the point (-2,-3)



Now let's find another point on the line:



That point has coordinates (4,-3).



Now let's find one more point on the line:



That point has coordinates (1,-3).



Now look at those three points on that line:

(-2,-3), (4,-3), (1,-3)

Notice that every one of those points has its
y coordinate equal to -3.  You can also see
that no matter how many points we get on that
line, every one of them will have -3 for its 
y-coordinate. 

So you merely
write that fact as "y always equals -3" 

and so it's equation is simply:

y = -3.

Edwin

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
The essential characteristic of a horizontal line is that the y-coordinates of every point on the line are equal, and the x-coordinates are the set of all real numbers.

In order for the line to pass through the point (-2,-3), every point on the line must have a y coordinate of -3. So the equation is simply y=-3.

Another way to look at it is that a horizontal line has a slope of zero, so using the point-slope form of the straight line: y-y%5B1%5D=m%28x-x%5B1%5D%29, you get:

y-%28-3%29=0%28x-%28-2%29%29

y%2B3=0

y=-3.