SOLUTION: The sum of 4 consecutive integers is one more than the third. Find the integers

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Question 125486: The sum of 4 consecutive integers is one more than the third. Find the integers
Answer by solver91311(24713) About Me  (Show Source):
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If the first integer is x, then the second must be x + 1, the third x + 2, and the fourth x + 3. Their sum must then be x%2B%28x%2B1%29%2B%28x%2B2%29%2B%28x%2B3%29. This sum is one more than the third. The third consecutive integer is x + 2, so one more than that is x + 3. Therefore we can write:

x%2B%28x%2B1%29%2B%28x%2B2%29%2B%28x%2B3%29=x%2B3

Removing the parentheses and collecting terms gets us to:
4x%2B6=x%2B3

Add -x to both sides and add -6 to both sides:
3x=-3

Divide by 3
x=-1

Therefore the integers are -1, 0, 1, and 2.

Check: -1 + 0 + 1 + 2 = 2, so the sum of the integers is 2.
The third is 1, and one more than that is 2. Answer checks.