SOLUTION: Good afternoon, does anyone know how to solve these two parts? Can you please provide the steps for clarification!! Thanks a bunch!! A) If {{{y=sqrt x+2}}}, fill in the followin

Algebra ->  Human-and-algebraic-language -> SOLUTION: Good afternoon, does anyone know how to solve these two parts? Can you please provide the steps for clarification!! Thanks a bunch!! A) If {{{y=sqrt x+2}}}, fill in the followin      Log On


   

Question 125459: Good afternoon, does anyone know how to solve these two parts? Can you please provide the steps for clarification!! Thanks a bunch!! A) If y=sqrt+x%2B2, fill in the following table for x = 0, 1, 2, 3, 4. Round to three decimal places where necessary.

X-----Y
0
1
2
3
4
B) Explain why no negative values are chosen as values to substitute in for x.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
y=sqrt(x+2)I'LL ASSUME YOU MEAN (X+2) UNDER THE SQRT.
Y=SQRT(0+2)=SQRT2=1.414
Y=SQRT(1+2)=SQRT3=1.732
Y=SQRT(2+2)=SQRT4=2
Y=SQRT(3+2)=SQRT5=2.236
Y=SQRT(4=2)=SQRT6=2.449
NO GOOD REASON FOR NOT INCLUDING NEGATIVE NUMBERS.
EXAMPLE:
Y=SQRT(-4+2)=SQRT(-2)=1.414i