SOLUTION: Jason has a pocket full of quarters and dimes. There are 58 more quarters than dimes and the total value of the change is $20.45. How many dimes are there?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Jason has a pocket full of quarters and dimes. There are 58 more quarters than dimes and the total value of the change is $20.45. How many dimes are there?       Log On


   

Question 125235:
Jason has a pocket full of quarters and dimes. There are 58 more quarters than dimes and the total value of the change is $20.45. How many dimes are there?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
Q=D+58 OR D=Q-58
.25Q+.10(Q-58)=20.45
.25Q+.10Q-5.8=20.45
.35Q=20.45+5.8
.35Q=26.25
Q=26.25/.35
Q=75 NUMBER OF QUARTERS.
D=75-58=17 NUMBER OF DIMES.
PROOF
.25*75+17*.10=20.45
18.75+1.70=20.45
20.45=20.45