SOLUTION: 17. Write an equation for a line perpendicular to Y=2/3x-5which contains point (2,4) (Points: 1) y = 2/3x + 4 y = -3/2x + 4 y = -3/2x + 7

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Question 125064: 17.

Write an equation for a line perpendicular to Y=2/3x-5which contains point (2,4)

(Points: 1)
y = 2/3x + 4
y = -3/2x + 4
y = -3/2x + 7
y = 2x + 6
is the answer C

Found 2 solutions by checkley71, MathLover1:
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website!
Y=2X/3-5 (RED LINE).
THIS LINE HAS A SLOPE OF 2/3. THUS A PERPENDICULAR LINE HAS A SLOPE OF -3/2.
4=-3/2*2+b
4=-3+b
b=4+3
b=7 IS THE Y INTERCEPT.
THUS THE EQUATION FOR THIS LINE IS:
Y=-3X/2+7 (GREEN LINE).
YES THE ANSWER IS (C).
(graph 200x200 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = 2x/3 -5 and y = -3x/2 +7).

Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website!
the answer is:
since given line which contains point (,), we will find a line perpendicular to using what we know:
we know

the slopes of the perpendicular lines are negative reciprocal; so the slope from the line will have negative reciprocal equal to
so, the slope of the unknown line must be ;

Slope

we also know that line goes through (,), and we can find the equation by plugging in this info into the formula
Point-Slope Formula:
where m is the slope and (x,x1) is the given point
Plug in, and ,