SOLUTION: find two consecutive numbers whose product is 72

Algebra ->  Sequences-and-series -> SOLUTION: find two consecutive numbers whose product is 72      Log On


   

Question 125006: find two consecutive numbers whose product is 72
Found 2 solutions by checkley71, josmiceli:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X(X+1)=72
X^2+X-72=0
(X+9)(X-8)=0
X+9=0
X=-9 ANSWER.
X-8=0
X=8 ANSWER.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
n%2A%28n+%2B+1%29+=+72
n%5E2+%2B+n+-+72+=+0
%28n+-+8%29%28n+%2B+9%29
The solutions are
n+=+8
n+=+-9
I choose n+=+8 since I want positive numbers
n+=+8
n+%2B+1+=+9
8%2A9+=+72 answer