SOLUTION: find two numbers consecutive pairs whose product is 80

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Question 124996: find two numbers consecutive pairs whose product is 80
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
MAYBE THIS IS NOT THE CORRECT ANSWER BECAUSE THE PROBLEM SHOULD BE:
"TWO COSECUTIVE ODD OR EVEN NUMBERS WHOSE PRODUCT IS 80"
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LET X & (X+1) BE THE 2 CONSECUTIVE NUMBERS.
X(X+1)=80
X^2+X-80=0
USING THE QUADRATIC EQUATION WE GET:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(-1+-SQRT[1^2-4*1*-80])/2*1
X=(-1+-SQRT[1+320])/2
X=(-1+-SQRT[321])/2
X=(-1+-17.92)/2
X=(-1+17.92)/2
X=16.92/2
X=8.46 ANSWER.
X=(-1-17.92)/2
X=-18.92/2
X=-9.46 ANSWER.