SOLUTION: Please help me solve this problem: Austin has nickels, dimes and quarters. He has a total of $17.65. He has eleven fewer quarters than nickels and six times as many dimes as quarte
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Question 12493: Please help me solve this problem: Austin has nickels, dimes and quarters. He has a total of $17.65. He has eleven fewer quarters than nickels and six times as many dimes as quarters. How many of each coin does he have?
You can put this solution on YOUR website! Let number of nickels be "x".
Then number of quarters is "x-11"
And number of dimes is "6(x-11)" = "6x-66"
Value of nickels is (5)x cents
Value of quarters is (25)(x-11)= 25x-275 cents
And Value of dimes is (10)(6x-11)= 60x-110 cents
EQUATION:
Value of nickels + Value of dimes + Value of quarters = 1765 cents
5x + 25x-275 + 60x-110 = 1765
90 x = 2150
x = 23.89... (number of nickels??????)
Answer doesn't nake sense since you can't have 23.89 nickels.
Cheers,
Stan H.
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