SOLUTION: Lane invested $10,000, part at 15% and part at 14%. If the total interest at the end of the year is $1,430, how much did she invest at 15%?

Algebra ->  Graphs -> SOLUTION: Lane invested $10,000, part at 15% and part at 14%. If the total interest at the end of the year is $1,430, how much did she invest at 15%?      Log On


   



Question 124910: Lane invested $10,000, part at 15% and part at 14%. If the total interest at the end of the year is $1,430, how much did she invest at 15%?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
.15X+.14(10,000-X)=1,430
.15X+1,400-.14X=1,430
.01X=1,430-1,400
.01X=30
X-30/.01
X=3,000 AMOUNT INVESTED @ 15%.
10,000-3,000=7,000 AMOUNT INVESTED @ 14%.
PROOF:
.15*3,000+.14*7,000=1,430
450+980=1,430
1,430=1,430