SOLUTION: suppose you have just enough money, in coins, to pay for a loaf of bread priced at $1.95. You have 12 coins, all quarters and dimes. Let q=quarters and d=dimes. What system would m

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Question 124866: suppose you have just enough money, in coins, to pay for a loaf of bread priced at $1.95. You have 12 coins, all quarters and dimes. Let q=quarters and d=dimes. What system would model this given information?
Answer by solver91311(24713) About Me  (Show Source):
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You have q quarters and d dimes. Since you have 12 coins, all of which are either quarters or dimes, red%28q%2Bd=12%29: Equation 1 of your system.

Also, the value of a quarter is 25 cents, so the value of all your q quarters is 25q cents. Likewise the value of your d dimes is 10d cents.

The total value of your money is $1.95, which can be expressed as 195 cents, therefore:
red%2825q+%2B+10d=195%29: Equation 2 of your system. Alternatively, if you didn't want to convert the $1.95 to cents, you could express the value of the quarters as .25q and the value of dimes as .10d, making the equation 0.25q%2B0.10d=1.95. I would rather deal with integer coefficients myself, but it is purely a matter of personal preference. Given proper solution methods and correct arithmetic, you will get the same answer either way.

So, how many of each coin do you have?