SOLUTION: Write f(x) as a product of three linear factors f(x)= x^3 -4x^2 -7x +10

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Question 124775: Write f(x) as a product of three linear factors

f(x)= x^3 -4x^2 -7x +10

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Given the cubic equation: ax%5E3%2Bbx%5E2%2Bcx%2Bd=0, the only possible rational roots are of the form x = factor of d/factor of a or x= -(factor of d/factor of a), so by trial and error find s such that %28x-s%29 divides the original equation by polynomial long division without a remainder.

For your problem, a = 1 and d = 10. The possible factors of d are 1, 2, and 5. 1 is the only factor of a. So if a rational root exists, it must be ±1, ±2, or ±5.

When I was working this out, I started with s = 1, dividing x%5E3+-4x%5E2+-7x+%2B10 by x-1. I got lucky, or so I thought.

The quotient after performing the polynomial long division, was x%5E2-3x-10

Now all that remains is to factor x%5E2-3x-10. -5%2A2=-10 and -5%2B2=-3, so our factors are %28x-5%29 and %28x%2B2%29. Turns out that luck wasn't a factor -- I had a 50-50 chance of finding the correct factor at the start, knowing that I had ±1, ±2, or ±5 to choose from.

Therefore: x%5E3+-4x%5E2+-7x+%2B10=green%28%28x-1%29%28x%2B2%29%28x-5%29%29

I'll let you multiply it out to check the answer.