SOLUTION: Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned
Algebra ->
Coordinate Systems and Linear Equations
-> SOLUTION: Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned
Log On
Question 124730: Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned home 40 hours after leaving. How many miles is City A from City B Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned home 40 hours after leaving. How many miles is City A from City B
:
First of all, let's just concern ourselves with the traveling time:
Subtract the 10 hr stay from the total time (40 hr) she was gone;
She had 30 hrs on the road
:
Let d = distance from A to B
:
Write a time equation: Time =
:
Time to B + time to A = 30 hrs + = 30
:
Multiply equation by a multiple of both denominators, 450 would do it:
450* + 450* = 450(30)
Cancel out the denominators and you have:
:
9d + 10d = 13500
:
19d = 13500
d =
d = 710.5 miles from A to B
:
:
Check solution by finding the time each way and finding the total time:
710.5/50 = 14.2 hrs
710.5/45 = 15.8 hrs
--------------------
Total time 30.0 hrs as given
;
:
Did I make this understandable? Any questions?