SOLUTION: Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned      Log On


   



Question 124730: Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned home 40 hours after leaving. How many miles is City A from City B
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned home 40 hours after leaving. How many miles is City A from City B
:
First of all, let's just concern ourselves with the traveling time:
Subtract the 10 hr stay from the total time (40 hr) she was gone;
She had 30 hrs on the road
:
Let d = distance from A to B
:
Write a time equation: Time = distance%2Fspeed
:
Time to B + time to A = 30 hrs
d%2F50 + d%2F45 = 30
:
Multiply equation by a multiple of both denominators, 450 would do it:
450*d%2F50 + 450*d%2F45 = 450(30)
Cancel out the denominators and you have:
:
9d + 10d = 13500
:
19d = 13500
d = 13500%2F19
d = 710.5 miles from A to B
:
:
Check solution by finding the time each way and finding the total time:
710.5/50 = 14.2 hrs
710.5/45 = 15.8 hrs
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Total time 30.0 hrs as given
;
:
Did I make this understandable? Any questions?