SOLUTION: Solve.
If a ball thrown vertically upward from a height of 64 feet, with an initial velocity of 48 ft/s, its height(h) after (t) second is given by
h= - 16t squared + 48t + 6
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If a ball thrown vertically upward from a height of 64 feet, with an initial velocity of 48 ft/s, its height(h) after (t) second is given by
h= - 16t squared + 48t + 6
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Question 124664: Solve.
If a ball thrown vertically upward from a height of 64 feet, with an initial velocity of 48 ft/s, its height(h) after (t) second is given by
h= - 16t squared + 48t + 64. How long does it take the ball to return to the ground? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! h= - 16t squared + 48t + 64. How long does it take the ball to return to the ground?
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The height of the ball is zero when it returns to the ground.
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EQUATION:
-16t^2 + 48t + 64 = 0
-16(t^2 - 3t + 4) = 0
(t-4)(t+1) = 0
Positive answer:
t = 4 seconds.
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Cheers,
Stan H.
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