SOLUTION: How many pounds of candyworth $3.60 per pound must be added to 10 pounds of chocolate worth $2.40 per pound to form a mixture worth $3.30 per pound?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many pounds of candyworth $3.60 per pound must be added to 10 pounds of chocolate worth $2.40 per pound to form a mixture worth $3.30 per pound?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 124563: How many pounds of candyworth $3.60 per pound must be added to 10 pounds of chocolate worth $2.40 per pound to form a mixture worth $3.30 per pound?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
3.6x+2.4*10=3.3(x+10)
3.6x+24=3.3x+33
3.6x-3.3x=33-24
.3x=9
x=9/.3
x=30 pounds of $3.60 candy is needed.
proof.
3.6*30+2.4*10=3.3*40
108+24=132
132=132