SOLUTION: Can anyone help me solve this equation? 160x=3x + the sqaure root of 50x+9000 160x-3x=the square root of 50x + 9000 is all the farther I've gotten. I think I square both sides

Algebra ->  Radicals -> SOLUTION: Can anyone help me solve this equation? 160x=3x + the sqaure root of 50x+9000 160x-3x=the square root of 50x + 9000 is all the farther I've gotten. I think I square both sides      Log On


   

Question 124427: Can anyone help me solve this equation?
160x=3x + the sqaure root of 50x+9000
160x-3x=the square root of 50x + 9000 is all the farther I've gotten. I think I square both sides now to get rid of the square root symbol, but do I need to simplify it first and if so, how?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
160x=3x + the sqaure root of 50x+9000
:
160x-3x=the square root of 50x + 9000
which is:
157x = sqrt(50x+9000)
:
Square it:
24649x^2 = 50x + 9000
:
Arrange as a quadratic equation
24649x^2 - 50x - 9000 = 0
:
you have to use the quadratic formula to solve it:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
In this equation a=24649; b=-50; c=-9000
x+=+%28-%28-50%29+%2B-+sqrt%28-50%5E2-+4+%2A+24649+%2A+-9000+%29%29%2F%282%2A24649%29+
:
x+=+%2850+%2B-+sqrt%282500+-+%28-887364000%29+%29%29%2F%2849298%29+
:
x+=+%2850+%2B-+sqrt%282500+%2B+887364000+%29%29%2F%2849298%29+
:
x+=+%2850+%2B-+sqrt%28887336500%29%29%2F%2849298%29+
Two solutions:
x+=+%2850+%2B+29788.7%29%2F%2849298%29+
x+=+%2829838.7%29%2F%2849298%29+
x = +.605
and
x+=+%2850+-+29788.7%29%2F%2849298%29+
x+=+%28-29738.7%29%2F%2849298%29+
x = -.603
:
I checked these solutions on a Ti83 graphing calc. You can confirm it yourself
by substitution in the original equation