Question 124316: I'm really stuck on this problem because I'm not sure where to start. I would really apprciate it if someone could walk me through the steps to get to the correct answer,thank you in advance for your time.:
Two crafty bacteria fall into a pot of milk which has recently been sterilized. They reproduce at a rate of 4% per day. Determine how many bacteria will be present after 100 days.
A 100
B 800
C 0
D 2
E 109
F 345
Answer by stanbon(13458)
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Day 1: 2
Day 2: 2+0.04*2=2(1+0.04)= 2*1.04
Day 3 = (2*1.04)+0.4*(2*1.04) = 2*1.04(1+0.04) = 2*(1.04)^2
....
...
Day 100 = 2*1.04^99 = 97
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Cheers,
Stan H.
*** Thank you so much for your responce,and although I follow the steps that you took,you came to an answer of 97. And thats not one of the choices,am I missing something? If anyone could help id very much appriciate it.
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! the technique is correct __ interpretation of the problem may be the difficulty
the problem states "after 100 days", with "after" being the key
the expression should probably be 2*1.04^100
__ unfortunately, this equates to 101, which is also NOT one of the choices
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