SOLUTION: The number N, in millions, of hearing impaired individuals of age x can be approximated by N = -0.00006x^3 + 0.006x^2 - 0.1x +1.3 Approximate to the nearest million the number o

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Question 124303: The number N, in millions, of hearing impaired individuals of age x can be approximated by N = -0.00006x^3 + 0.006x^2 - 0.1x +1.3
Approximate to the nearest million the number of hearing impaired individuals of ages 50 - 60.
N = ____ million individuals of age 50.
N = ____ million individuals of age 60.
Can you help? This is not from a textbook.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The number N, in millions, of hearing impaired individuals of age x can be approximated by:
:
N = -0.00006x^3 + 0.006x^2 - 0.1x + 1.3
:
Approximate to the nearest million the number of hearing impaired individuals of ages 50 - 60.
N = ____ million individuals of age 50.
:
N = -0.00006x^3 + 0.006x^2 - 0.1x + 1.3
:
Substitute 50 for x in the above equation:
N = -0.00006(50^3) + 0.006(50^2) - 0.1(50) + 1.3
N = -7.5 + 15 - 5 + 1.3
N = 3.8 million age 50
:
:
N = ____ million individuals of age 60.
:
Substitute 60 for x in the above equation:
N = -0.00006(60^3) + 0.006(60^2) - 0.1(60) + 1.3
N = -12.96 + 21.6 - 6 + 1.3
N = 3.94 million age 60
:
Now do they mean total number of deaf people at all ages from 50 to 60?
:
Using the average of of the two ages and multiplying that by 10 it would be:
%28%283.8%2B3.94%29%29%2F2 * 10 = 38.7 million ages 50 to 60