SOLUTION: Find the domain and range {{{f(x)=sqrt (x^2-49)}}}

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Question 124280This question is from textbook college algebra
: Find the domain and range
f%28x%29=sqrt+%28x%5E2-49%29 This question is from textbook college algebra

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Domain is all x such that f(x) makes sense. Values inside a square root sign must be greater than or equal to 0.
x%5E2-49%3E=0
x%5E2%3E=49
x%3E=7
x%3C=-7
The domain is therefore all x except the range (-7,7) or the domain is
(-infinity,7] U [7,-infinity)
The brackets indicate that -7 and 7 belong in the domain.
The range is from [0,infinity).