SOLUTION: A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip a
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip a
Log On
Question 124186: A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y
:
Let d = distance from x to y
:
Write a time equation; time =
Different speed roundtrip time = 1 speed roundtrip time + half/hour + = +
Multiply equation by 1800 to get rid of the denominators:
1800* + 1800* = 1800* + 1800*
Cancel the denominators and you have:
:
36d + 45d = 40(2d) + 900
:
81d = 80d + 900
:
81d - 80d = 900
:
d = 900 miles from x to y
:
:
Check solution in: + = + + = +
18 + 22.5 = 40 + .5; confirms out solution
