Question 124184: Appreciate your help in accomplishing this problem. This is an instructor generated question and having problems understanding and getting started.
A basketball player makes free throw shots 80% of the time. If the player attempts 10 free throw shots,
a. What is the expected value (mean) of the number of free throw shots the player makes
b. What is the standard deviation of the number of free throw shots the player makes?
c. What is the probability that the player makes at least three shots?
d. What is the probability that the player makes between 7 and 9 shots, inclusively?
Appreciate any assistance you can provide. (I know we have to a table to assist with finding the solutions)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A basketball player makes free throw shots 80% of the time. If the player attempts 10 free throw shots,
a. What is the expected value (mean) of the number of free throw shots the player makes
Since he either makes or misses each shot this is a binomial problem.
The mean for binomial is np
Your answer is np = 20*0.8 = 16
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b. What is the standard deviation of the number of free throw shots the player makes?
The standard deviation is sqrt(npq) = sqrt(16*0.2) = 1.7888..
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c. What is the probability that the player makes at least three shots?
You have a chart and I have a TI-83 calculator.
I get 1-binomcdf(20,0.8,2) is approximately 1.
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d. What is the probability that the player makes between 7 and 9 shots, inclusively?
I get binomcdf(20,0.8,9)-binomcdf(20,0.8,6)= 0.00056
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Cheers,
Stan H.
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