SOLUTION: Given f(x)=5x+3 and g(x)=x2-2 find each value g(5) 5[g(3)]

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Question 124164: Given f(x)=5x+3 and g(x)=x2-2 find each value
g(5)
5[g(3)]

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
The problem does not require you to know that f(x) = 5x +3. That is just extra information that
is not used.
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You are told that:
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g%28x%29+=+x%5E2+-2
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and you are first told to find g(5). All you have to do to work this problem is to go to the
equation for g(x), replace every x in it with 5, and evaluate the result. So you begin with:
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g%28x%29+=+x%5E2+-2
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then replace every x by 5 to get:
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g%285%29+=+5%5E2+-2
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and evaluate it by squaring the 5 and subtracting 2 as follows:
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g%285%29+=+5%5E2+-2+=+25+-+2+=+23
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So the answer to your first problem is:
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g%285%29+=+23
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The second problem ... evaluating 5[g(3)] is done by first finding g(3) and then multiplying that
value by 5.
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To find g(3) first go to the equation for g(x), replace every x with 3, and evaluate the
result. So begin with:
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g%28x%29+=+x%5E2+-2
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then replace every x with 3 and you have:
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g%283%29+=+3%5E2+-2+
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to evaluate this, square the 3 and subtract 2 as follows:
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g%283%29+=+3%5E2+-2+=+9+-+2+=+7
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So you have:
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g%283%29+=+7
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Then to find 5 times g(3) just multiply both sides by 5 to get:
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5%2Ag%283%29+=+5%2A7+
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multiply out the right side of this equation and you get:
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5%2Ag%283%29+=+5%2A7+=+35
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So the answer to your second problem is just:
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5%2Ag%283%29+=+35
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Hope this helps you to understand the problem a little better.
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