SOLUTION: The length of a rectangular garden is 7 ft. more than twice its width. If the perimeter of the garden is 56 ft., find the width of the rectangle.
Algebra ->
College
-> Linear Algebra
-> SOLUTION: The length of a rectangular garden is 7 ft. more than twice its width. If the perimeter of the garden is 56 ft., find the width of the rectangle.
Log On
Question 124095: The length of a rectangular garden is 7 ft. more than twice its width. If the perimeter of the garden is 56 ft., find the width of the rectangle. Answer by PBMathandscience(9) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 2x(Length + Width). Let W be the width. Then the length is W+7. The resultant equation is:
56=2*((W+7)+W)
Divide both sides by 2;
28=W+7+W
Subtract 7 from both sides:
21 = 2*W
Divide by 2
10.5=W
Check: 2*((10.5+7)+10.5)=2*(17.5+10.5)=2*(28)=56.
Solution checks.
(