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Question 124046: The problem reads:
Write the standard form of the equation of the line passing through the point (2,-4) and perpendicular to the line y= -3/7x-2
I have tried to use point-slope form, but it isn't right.
Please help me with this problem.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Write the standard form of the equation of the line passing through the point (2,-4) and perpendicular to the line y= -3/7x-2
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The given line has slope -3/7 so the perpendicular line must have slope = 7/3
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Your line has form y = mx+b and you know y,x, and m; so solve for b.
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-4=(7/3)2 + b
-4=14/3 + b
-12/3 = 14/3 + b
b = -26/3
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EQUATION:
y = (7/3)x - (26/3)
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Cheers,
Stan H.
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