SOLUTION: Problem Solving With Systems of A line: How to Solve
Suppose you have 10 coins that total $0.85. Some of the coins are dimes, and others are nickels. How many of each coin is ther
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-> SOLUTION: Problem Solving With Systems of A line: How to Solve
Suppose you have 10 coins that total $0.85. Some of the coins are dimes, and others are nickels. How many of each coin is ther
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Question 123813: Problem Solving With Systems of A line: How to Solve
Suppose you have 10 coins that total $0.85. Some of the coins are dimes, and others are nickels. How many of each coin is thers? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! n+d=10 or n=10-d
.05n+.10d=.85
.05(10-d)+.10d=.85
.5-.05d+.10d=.85
.05d=.35
d=.35/.05
d=7 number of dimes.
10-7=3 number of nickels.
proof
.05*3+.10*7=.85
.15+.70=.85
.85=.85
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