Question 123792This question is from textbook
: a developer purchased 70 acres of land for 900000 dollars. if part costs 20000 dollars per acre and the remainder cost 10000 per acre how many acres did the developer buy at each price.
This question is from textbook
Answer by PBMathandscience(9)   (Show Source):
You can put this solution on YOUR website! Call the area purchased at 20,000 per acre as X. Then the portion purchased at 10,000 per acre is (70-X).
Since the total cost is 900,000 we have the following equation:
900,000 = 20,000*X + 10,000*(70-X)
or
900,000 = 20,000*X + 700,000 - 10,000*X
0r
200,000 = 10,000 * X
20 = X
So the developer purchased 20 acres at 20,000 and (70-20) or 50 acres at 10,000.
Check:
20*20,000 + 50*10,000 = 400,000 + 500,000 = 900,000
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