SOLUTION: Find three consecutive (not even) integers such that the sum of the twice the first, six times the second and three times the third is 133.

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Question 123682: Find three consecutive (not even) integers such that the sum of the twice the first, six times the second and three times the third is 133.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
x, x+1, x+2 are the integers.
2x+6(x+1)+3(x+2)=133
2x+6x+6+3x+6=133
11x=133-12
11x=121
x=121
11x=11 answer for the first integer.
11=1=12
11+2=13
proof:
2*11+6*12+3*13=133
22+72+39=133
133=133