Question 12349: A consumer goods manufacturer wanted to blend two grades of coffee, one costing $1.50 per kg., the other 200 kg. costing $1.90 per kg., to be sold off at $1.60 per kg. How much coffee costing $1.50 per kg. would be needed?
This is a new lesson. Please help solve this problem.
Answer by kusha(21)   (Show Source):
You can put this solution on YOUR website! your problem is wrong and the statement should read to make a mixture costing $1.60 per KG and not to be sold off at 1.60 per kg
Now this is an alligation question the ratio of cheaper qtty to dearer qtty can be solved by the formula
c:d = (d-m)/(m-c)
c - cheaper qtty(1.5 in this case), d: dearer qtty(1.9 in this case), m: mean qtty(1.6 in this case)
So c:d = (1.9-1.6)/(1.6-1.5)
on solving the ratio is 3:1 so if dearer qtty is 1 cheaper qtty is 3
thus if dearer qtty is 200 kg, the cheaper qtty should be 600 Kg.
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