Question 123286: How many ounces of water should a chemist mix with 16 ounces of a 25% sulfuric acid solution to reduce it to a 10% solution? Found 2 solutions by stanbon, Superownage:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many ounces of water should a chemist mix with 16 ounces of a 25% sulfuric acid solution to reduce it to a 10% solution?
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25% solution DATA:
Amt = 16 oz ; amt of active ingredient = 0.25*16 = 4 oz
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Water solution DATA:
Amt = x; amt of active ingredient = 0*x = 0 oz
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10% Mixture DATA:
Amt. = 16+x oz ; active ingredient = 0.10(16+x)= 1.6+0.1x oz
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EQUATION:
active + active = active
4+0 = 1.6+0.1x
2.4 = 0.1x
x = 24 oz (amount of water needed for the mixture)
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Cheers,
Stan H.
You can put this solution on YOUR website! watch this
25% of 16 is 4,10%=0.10=1/10 the inverse or reciprocal; how to make it an 100% is to multiply by 10,4 x 10 = 40-16=24. your solution is 24.
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