SOLUTION: Law of cosines
solve the triangle. Round lengths of sides to the nearest tenth and measures of angles to the nearest degree
a=16, b=20, m angle B=40
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solve the triangle. Round lengths of sides to the nearest tenth and measures of angles to the nearest degree
a=16, b=20, m angle B=40
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Question 123269: Law of cosines
solve the triangle. Round lengths of sides to the nearest tenth and measures of angles to the nearest degree
a=16, b=20, m angle B=40 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve the triangle. Round lengths of sides to the nearest tenth and measures of angles to the nearest degree
a=16, b=20, m angle B=40
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sin(A)/a = sin(B)/b
sin(A) = 16[sin(40)/20]
sin(A) = 0.5142
A = 30.5142 degrees
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C = 180-(30.5142+40)= 109.054 degrees
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c = a^2+b^2-abcos(C)
c^2 = 16^2 + 20^2 - 16*20cos(109.054)
c = 27.623
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Cheers,
Stan H.
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