SOLUTION: I am in 7th grade pre algebra and need help with my inequalities homework please. Here is one of them I do not understand: d - 5 ≤ - 11 Thank you.

Algebra ->  Inequalities -> SOLUTION: I am in 7th grade pre algebra and need help with my inequalities homework please. Here is one of them I do not understand: d - 5 ≤ - 11 Thank you.      Log On


   



Question 123241: I am in 7th grade pre algebra and need help with my inequalities homework please. Here is one of them I do not understand: d - 5 ≤ - 11
Thank you.

Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Discussion



Solve inequalities just like you would solve equations. There are two very
important differences.
1. Instead of a single element in the solution set that you would get with
a linear equation in a single variable, with an inequality you get a solution
set with an infinite number of elements represented by a number line interval.

2. When, in the process of solving the inequality, you need to multiply or
divide by a negative number, you must reverse the sense of the inequality.
Here's why:

2%3C3, but %28-1%29%282%29%3E%28-1%29%283%29 because -2%3E-3.





Solution



d-5%3C=11

Just like an equation, you can add the same value to both sides:
d-5%2B5%3C=11%2B5

d%3C=16

Therefore, the solution set is all real numbers such that -infinity%3Cd%3C=16





Check Answer



The solution interval says that d=16 is a solution, so check:
Is 16-5%3C=11 a true statement? Yes, 11%3C=11

The solution interval implies that anything smaller than 16 is a solution:
Is 10-5%3C=11 a true statement? Yes, 5%3C=11

The solution interval implies that anything larger than 16 is NOT a solution:
Is 17-5%3C=11 a false statement? Yes, 12 is NOT less than or equal to 11.

Answer checks.


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
d - 5 ≤ - 11
Add 5 to both sides to the inequality to get:
d <= -6
=============
Cheers,
Stan H.