SOLUTION: 3x+y<9 , the < or > signs means equal to or greater or lesser than. x-y<7, the > has a line under it. Didn't know how to make it on here. x>0, Which of the followin

Algebra ->  Inequalities -> SOLUTION: 3x+y<9 , the < or > signs means equal to or greater or lesser than. x-y<7, the > has a line under it. Didn't know how to make it on here. x>0, Which of the followin      Log On


   



Question 123204: 3x+y<9 , the < or > signs means equal to or greater or lesser than.
x-y<7, the > has a line under it. Didn't know how to make it on here.
x>0,
Which of the following points satisfy the inequalities?
(2,5), ( 0,9), (3,-2) or (-1,0)

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The best way is to plot these
(1) 3x+%2B+y+%3C+9
(2) x+-+y+%3C+7
(3) x+%3E+0
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Find y in terms of x
(1) 3x+%2B+y+%3C+9
y+%3C+-3x+%2B+9
(2) x+-+y+%3C+7
-y+%3C+-x+%2B+7
multiply both sides by -1 and reverse the < sign
y+%3E+x+-+7
(3) x+%3E0 No y involved here. This is saying that x
can never be 0 or negative. It's domain is the right half of
the graph
I'll do a plot of
y+%3C+-3x+%2B+9 and
y+%3E+x+-+7
+graph%28+600%2C+600%2C+-2%2C+30%2C+-15%2C+15%2C+-3x+%2B+9%2Cx+-+7%29
The solution is the little triangular area bounded by the y axis
and the lines. Now see which points are in that area
-----------------
(2,5) looks to be just outside, and it fails (1) because
y+%3C+-3x+%2B+9
5+%3C+%28-3%29%2A2+%2B+9
5+%3C+-6+%2B+9
5+%3C+3 This is clearly not true
------------------
(0,9) This looks like it might be in the area, but it fails (1) also
y+%3C+-3x+%2B+9
9+%3C+%28-3%29%2A0+%2B+9
9+%3C+9 This is clearly not true also
------------------
(3,-2) This fails in the area
------------------
(-1,0) x can't be negative, as I said, and it is
also clearly outside the area
-------------------
So, only (3,-2) satisfies the inequalities answer