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Question 123097: A tent manufacturer produces two models, the Outback and the Bush Walker. From earlier sales records it is known that 20 per cent more of the Outback model is sold than the Bush Walker. A profit of $200 is made on each Outback sold, but $350 is made on each Bush walker. If during the next year a profit of $177000 is planned, how many of each model must be sold.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A tent manufacturer produces two models, the Outback and the Bush Walker. From earlier sales records it is known that 20 per cent more of the Outback model is sold than the Bush Walker. A profit of $200 is made on each Outback sold, but $350 is made on each Bush walker. If during the next year a profit of $177000 is planned, how many of each model must be sold.
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Let x = no. of Outbacks
Let y = no. of BushW
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Write an equation for what is described here
200x + 350y = 177000
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One equation, two unknowns!!!
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But wait, it says,
"20 per cent more of the Outback model is sold than the Bush Walker"
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Therefore we can say: x = 1.2y
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Substitute 1.2y for x in the equation, and find y
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200(1.2y) + 350y = 177000
240y + 350y = 177000
590y = 177000
y = 
y = 300 BushW
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Find x
x = 1.2(300)
x = 360 Outbacks
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Check our solutions in the original equation
200(360) + 350(300) =
72000 + 105000 = 177000 as given
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Not that hard, right?
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