Question 123007This question is from textbook Algebra I
: It contains a graph to find the constant of a slope. I know how to find the slope but not a constant, teacher is not helpful, he describes the problem so he knows it, which is not helpful to children.
The problem shows a graphy with a blue line stretching from Q2's top left corner and reaching Q4's bottom right corner. In Q4 it shows a blue dot at
(2,-2) then another blue dot at (0,0) Then it says y= -x
I cannot seem to figure this out
This question is from textbook Algebra I
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403)   (Show Source):
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The problem shows a graphy with a blue line stretching from Q2's top left corner and reaching Q4's bottom right corner. In Q4 it shows a blue dot at
(2,-2) then another blue dot at (0,0) Then it says y= -x
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You have a line that passes thru (2,-2) and (0,0)
The slope = (change in y)/(change in x) = (-2-0)/(2-0) = -2/2 = -1
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The equation of the line can be written as y = mx + b
You know m=-1, and y=0 when x =0
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You substitute those values in the equation to find "b":
0 = -1*0 + b
0 = 0 +b
b = 0
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So the equation of the graph is y = (-1)x+0
or simply y = -x
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Hope that helps.
Cheers,
Stan H.
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