SOLUTION: A bullet is fired horizontally at a target, and the sound of its impact is heard 0.9 seconds later. If the speed of the bullet is 3190 ft/sec and the speed of sound is 1100 ft/sec

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Question 122672This question is from textbook algebra and trigonometry with analiytic geometry
: A bullet is fired horizontally at a target, and the sound of its impact is heard 0.9 seconds later. If the speed of the bullet is 3190 ft/sec and the speed of sound is 1100 ft/sec, how far away is the target?
Give your answer correct to the nearest tenth of a foot. This question is from textbook algebra and trigonometry with analiytic geometry

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A bullet is fired horizontally at a target, and the sound of its impact is heard 0.9 seconds later. If the speed of the bullet is 3190 ft/sec and the speed of sound is 1100 ft/sec, how far away is the target?
:
Let d = distance to the target
:
Write a time equation: Time = Distance/speed
:
Bullet transit time + sound transit time = .9 sec
d%2F3190 + d%2F1100 = .9
:
multiply equation by 3190*1100 = 3509000, to get rid of the denominators
3509000*d%2F3190 + 3509000*d%2F1100 = 3509000(.9)
Cancel out the denominators and you have:
:
1100d + 3190d = 3158100
:
4290d = 3158100
d = 315800%2F4290
d = 736.2 ft to the target
:
:
Check solution:
736.2%2F3190 + 736.2%2F1100 =
.23 + .67 = .9 sec; confirms our solution