SOLUTION: The length of a rectangle is 3 in. more than twice its width. If the perimeter of the rectangle is 36 in., what's the width of the rectangle?

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Question 122660: The length of a rectangle is 3 in. more than twice its width. If the perimeter of the rectangle is 36 in., what's the width of the rectangle?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let L=length, w=width
Since the length is "3 in. more than twice its width", this means: L=2w%2B3


P=2w%2B2L Start with the perimeter formula


36=2w%2B2%282w%2B3%29 Plug in the given perimeter P=36 and L=2w%2B3


36=2w%2B4w%2B6 Distribute


36=6w%2B6 Combine like terms on the right side


0=6w%2B6-36Subtract 36 from both sides


-6w=6-36 Subtract 6w from both sides


-6w=-30 Combine like terms on the right side


w=%28-30%29%2F%28-6%29 Divide both sides by -6 to isolate w



w=5 Divide

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Answer:
So our answer is w=5



So the width is 5 inches