SOLUTION: Use quadratic formula to solve 4x^2-8x+1=0....... I answered (8+-4sqrt3)/8 on a quiz and got it wrong. Thanks.

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Question 122453This question is from textbook Trigonometry
: Use quadratic formula to solve 4x^2-8x+1=0.......
I answered (8+-4sqrt3)/8 on a quiz and got it wrong.
Thanks. This question is from textbook Trigonometry

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!

4x%5E2-8x%2B1=0

a = 4
b = -8
c = 1

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ 
x+=+%28-%28-8%29+%2B-+sqrt%28+%28-8%29%5E2-4%2A4%2A1+%29%29%2F%282%2A4%29+ 
x+=+%288%2B-sqrt%2864-16%29%29%2F8+ 
x+=+%288%2B-sqrt%2848%29%29%2F8
x+=+%288%2B4sqrt%283%29%29%2F8 or x+=+%288-4sqrt%283%29%29%2F8

Your answer was technically correct, but you should have reduced it to lowest terms:

x=%282%2B-sqrt%283%29%29%2F2