SOLUTION: The perimeter of a rectangle is 76 cm. The length of the rectangle is eight more than four times its width. What are the dimensions of the rectangle?

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Question 122404: The perimeter of a rectangle is 76 cm. The length of the rectangle is eight more than four times its width. What are the dimensions of the rectangle?
Answer by algebrapro18(249) About Me  (Show Source):
You can put this solution on YOUR website!
to do this problem you need to set up a system of equations and solve.

w = width
l = length

2l+2w = 76
l = 8+4w

Now we substitute l = 8+4w into 2l+2w = 76 and solve for w.

2(8+4w)+2w = 76 -->distribute
16+8w+2w = 76 --> combine like terms
10w+16=76 --> subtract 16 from both sides
10w = 60 --> divide both sides by 10
w = 6

now we substitute that value into the equation for l and solve for l.

l = 8+4w --> plug in w=6
l = 8+4(6)--> multiply 4 by 6
l = 8 + 24--> add
l = 32

so the length is 32 cm and the width is 6 cm.