SOLUTION: A pharmicis has 200 milliliters of a solution that is 40% active ingredient. How much pure water should she add to the solution to get a solution that is 25% active ingredient?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A pharmicis has 200 milliliters of a solution that is 40% active ingredient. How much pure water should she add to the solution to get a solution that is 25% active ingredient?
Log On
Question 122323: A pharmicis has 200 milliliters of a solution that is 40% active ingredient. How much pure water should she add to the solution to get a solution that is 25% active ingredient? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! 80=50+.25X
.25X=80-50
.25=30
X=30/.25
X=120 AMOUNT OF PURE WATER NEEDED TO MAKE THE PROPER MIX.
.4*200=.25(200+120)
80=.25*320
80=80