Let
, which means that
Now substitute:
is factorable
=>
or
, so you really don't need the
quadratic formula to solve it. But since the question asked for it, here
it is
a = 1
b = -3
c = 2
=>
or
And no surprise, the roots are still 1 and 2.
But remember
If
then
or
=>
or
If
then
or
This gives us a total of four roots for the original quartic (degree 4)
equation as the Fundamental Theorem of Algebra would lead us to suspect.
Just for fun, let's check the notion graphically:
Note that the graph intersects the x-axis in 4 places and the x-coordinates of
these 4 places are equal to the roots or zeros of the given equation.
How very tidy.