SOLUTION: 2. The following equation has degree 4 because the highest power of the variable x is 4: x^4 – 3 x^2 + 2 = 0. Explain how one can use the quadratic formula to solve this equation

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Question 122287: 2. The following equation has degree 4 because the highest power of the variable x is 4:
x^4 – 3 x^2 + 2 = 0.
Explain how one can use the quadratic formula to solve this equation by using a change of variable. Solve this equation completely.

Found 2 solutions by josmiceli, solver91311:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E4+%96+3x%5E2+%2B+2+=+0
z+=+x%5E2
z%5E2+-+3z+%2B+2+=+0
%28z+-+2%29%28z+-+1%29+=+0
z+=+2
z+=+1
x%5E2+=+2
x%5E2+=+1
x+=+0+%2B-sqrt%282%29
x+=+0+%2B-sqrt%281%29
The solutions are:
x+=+sqrt%282%29
x+=+-sqrt%282%29
x+=+1
x+=+-1

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!



Let t=x%5E2, which means that t%5E2=x%5E4

Now substitute:



t%5E2-3t%2B2=0 is factorable

%28t-1%29%28t-2%29=0 => t=1 or t=2, so you really don't need the
quadratic formula to solve it. But since the question asked for it, here
it is
a = 1
b = -3
c = 2
t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
t+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%2A%281%29%2A%282%29+%29%29%2F%282%2A%281%29%29+
t+=+%283+%2B-+sqrt%28+9-8+%29%29%2F2 => t=%283%2B1%29%2F2=4%2F2=2 or t=%283-1%29%2F2=2%2F2=1
And no surprise, the roots are still 1 and 2.

But remember t=x%5E2

If t=1 then x=%2Bsqrt%281%29 or x=-sqrt%281%29 => x=1 or x=-1
If t=2 then x=%2Bsqrt%282%29 or x=-sqrt%282%29

This gives us a total of four roots for the original quartic (degree 4)
equation as the Fundamental Theorem of Algebra would lead us to suspect.

Just for fun, let's check the notion graphically:

graph%28600%2C600%2C-5%2C5%2C-5%2C5%2Cx%5E4-3x%5E2%2B2%29

Note that the graph intersects the x-axis in 4 places and the x-coordinates of
these 4 places are equal to the roots or zeros of the given equation.
How very tidy.