SOLUTION: Find the smallest positive number that is divisible by 7 with a remainder of 4, divisible by 8 with a remainder of 5, and divisible by 9 with a remainder of 6.

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: Find the smallest positive number that is divisible by 7 with a remainder of 4, divisible by 8 with a remainder of 5, and divisible by 9 with a remainder of 6.      Log On


   



Question 122255: Find the smallest positive number that is divisible by 7 with a remainder of 4, divisible by 8 with a remainder of 5, and divisible by 9 with a remainder of 6.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!

If a zero quotient is acceptable, then the answers are 4, 5, and 6.
If the quotient must be at least 1 to qualify for your instructor's
definition of 'divisible', then the answers are:
7 + 4 = 11,
8 + 5 = 13,
and 9 + 6 =15.


The relationship is:


N+=+%28Q+%2A+D%29+%2B+R where N is the number (also referred to as the dividend),
Q is the quotient, D is the divisor, and R is the remainder.


So for your first example:  N is what we want to determine, Q is either 0 or 1
depending on what 'divisible' means, D is 7, and R is 4.  Hence:


%280%2A7%29%2B4=4 or %281%2A7%29%2B4=11


I'll let you work out the other two.