SOLUTION: The total distance was 540 miles. Part of the joureny was on a motorcylce at 40 mph and PART WAS IN A CAR AT 60 Mph. What distance was covered by motorcycle if the total time of th

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Question 122253: The total distance was 540 miles. Part of the joureny was on a motorcylce at 40 mph and PART WAS IN A CAR AT 60 Mph. What distance was covered by motorcycle if the total time of the journey was 11 hours?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The basic formula is d=rt.

Let's call the distance travelled by the motorcycle d%5B1%5D, the
motorcycle's rate r%5B1%5D, and the time spent on the motorcycle t%5B1%5D.
Hence, for the motorcycle part of the trip we have d%5B1%5D=r%5B1%5Dt%5B1%5D.
Since we are given the motorcycle's speed, we can write d%5B1%5D=40t%5B1%5D.

Likewise for the car part of the trip we have d%5B2%5D=r%5B2%5Dt%5B2%5D, and
substituting the given speed we have d%5B2%5D=60t%5B2%5D.

We also know that the total distance is 540 miles, so we can say:
d%5B1%5D%2Bd%5B2%5D=540

And we know that the total time is 11 hours, so we can say:
t%5B1%5D%2Bt%5B2%5D=11

From here we need to find a way to express a relationship that is an equation
in one variable.

d%5B1%5D%2Bd%5B2%5D=540 => d%5B2%5D=540-d%5B1%5D and
t%5B1%5D%2Bt%5B2%5D=11 => t%5B2%5D=11-t%5B1%5D

Next we can substitute these two expressions for d%5B2%5D and t%5B2%5D
into the equation that we developed to describe the car part of the trip, thus:

d%5B2%5D=60t%5B2%5D
540-d%5B1%5D=60%2811-t%5B1%5D%29

Simplifying and collecting like terms gives us:
540-d%5B1%5D=660-60t%5B1%5D
-d%5B1%5D=660-540-60t%5B1%5D
-d%5B1%5D=120-60t%5B1%5D
d%5B1%5D=60t%5B1%5D-120

Recalling the equation that we developed for the motorcycle part of the trip:
d%5B1%5D=40t%5B1%5D, we now have two different expressions for d%5B1%5D in terms of t%5B1%5D that we can equate, since d%5B1%5D=d%5B1%5D.

40t%5B1%5D=60t%5B1%5D-120

Solving:
40t%5B1%5D-60t%5B1%5D=-120
-20t%5B1%5D=-120
t%5B1%5D=6
Now we know that the motorcycle part of the trip took 6 of the 11 hours total
time. Substituting this value into the original equation for the motorcycle
portion we get:
d%5B1%5D=40%2A6=240
Giving us 240 miles for the distance traveled by motorcycle.


Check the answer
The car part of the trip must have taken 11+-+6+=+5 hours, so the car
distance must have been 60%2A5=300 miles.

240+%2B+300=540 which was the given total distance. Answer checks.