SOLUTION: I am supposed to write the equation of the line that is parallel to the given line and passes through the given point. I am stuck. this is what I have. Here is the equation y=x

Algebra ->  Graphs -> SOLUTION: I am supposed to write the equation of the line that is parallel to the given line and passes through the given point. I am stuck. this is what I have. Here is the equation y=x      Log On


   

Question 122156: I am supposed to write the equation of the line that is parallel to the given line and passes through the given point. I am stuck. this is what I have.
Here is the equation
y=x - 3(1,-1)
Here is what I have
y=mx + b
-1=1 - 3
-1=-2
-1 + 2=-2 +2


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let's find the equation of the line that is parallel to y=x-3 and goes through (1,-1)

Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Since any two parallel lines have the same slope we know the slope of the unknown line is 1 (its from the slope of y=1%2Ax-3 which is also 1). Also since the unknown line goes through (1,-1), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope and (x%5B1%5D,y%5B1%5D) is the given point



y%2B1=1%2A%28x-1%29 Plug in m=1, x%5B1%5D=1, and y%5B1%5D=-1



y%2B1=1%2Ax-%281%29%281%29 Distribute 1



y%2B1=1%2Ax-1 Multiply



y=1%2Ax-1-1Subtract -1 from both sides to isolate y

y=1%2Ax-2 Combine like terms

So the equation of the line that is parallel to y=1%2Ax-3 and goes through (1,-1) is y=1%2Ax-2


So here are the graphs of the equations y=1%2Ax-3 and y=1%2Ax-2



graph of the given equation y=1%2Ax-3 (red) and graph of the line y=1%2Ax-2(green) that is parallel to the given graph and goes through (1,-1)