SOLUTION: I am stuck on this linear equation. I also need to find the rise over run too. This is what I have so far. 2x + 4y + 1 = 0 4y = 2x - 1 /4 /4 /4 y = 2/4x -1/4 y = 1/2

Algebra ->  Graphs -> SOLUTION: I am stuck on this linear equation. I also need to find the rise over run too. This is what I have so far. 2x + 4y + 1 = 0 4y = 2x - 1 /4 /4 /4 y = 2/4x -1/4 y = 1/2      Log On


   

Question 122153: I am stuck on this linear equation. I also need to find the rise over run too. This is what I have so far.

2x + 4y + 1 = 0
4y = 2x - 1
/4 /4 /4
y = 2/4x -1/4
y = 1/2x -1/4
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You made a mistake in converting to slope-intercept form

"4y = 2x - 1" <--- In this step, it should be -2x since you subtract 2x from both sides


So the equation in slope-intercept form is


y+=+-%281%2F2%29x+-1%2F4





Looking at y=-%281%2F2%29x-1%2F4 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-1%2F2 and the y-intercept is b=-1%2F4


Since b=-1%2F4 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is -1%2F2, this means:

rise%2Frun=-1%2F2


which shows us that the rise is -1 and the run is 2. This means that to go from point to point, we can go down 1 and over 2



So starting at , go down 1 unit


and to the right 2 units to get to the next point



Now draw a line through these points to graph y=-%281%2F2%29x-1%2F4

So this is the graph of y=-%281%2F2%29x-1%2F4 through the points and