SOLUTION: How do I solve 3+ (square root of) x^2-8x = 0 ? Please note I do not know how to put the square root sign, but x^2-8x is under the square sign.

Algebra ->  Radicals -> SOLUTION: How do I solve 3+ (square root of) x^2-8x = 0 ? Please note I do not know how to put the square root sign, but x^2-8x is under the square sign.      Log On


   



Question 122119: How do I solve 3+ (square root of) x^2-8x = 0 ? Please note I do not know how to put the square root sign, but x^2-8x is under the square sign.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
subtracting 3 __ sqrt(x^2-8x)=-3

squaring __ x^2-8x=9

subtracting 9 __ x^2-8x-9=0

factoring __ (x-9)(x+1)=0