SOLUTION: Q: For a particular event, 812 tickets were sold for a total of $1912. If students paid $2 per ticket and nonstudents paid $3 per ticket, how many student tickets were sold? Tota

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Question 122035: Q: For a particular event, 812 tickets were sold for a total of $1912. If students paid $2 per ticket and nonstudents paid $3 per ticket, how many student tickets were sold?
Totally stumped!!!!

Found 2 solutions by josmiceli, solver91311:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let s = number of students who bought tickets
Let n = number of non-students who bought tickets
2s+%2B+3n+=+1912
n+%2B+s+=+812
n+=+812+-+s
substitute n in terms of s into first equation
2s+%2B+3%28812+-+s%29+=+1912
2s+%2B+2436+-+3s+=+1912
s+=+2436+-+1912
s+=+524 answer
check
n+=+812+-+s
n+=+288
2s+%2B+3n+=+1912
2%2A524+%2B+3%2A288+=+1912
1048+%2B+864+=+1912
1912+=+1912
OK

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
This is the same as one of those coin problems where you have to figure out how many dimes and nickels you have. You will have two equations in two variables, one of the equations shows the relationship between the numbers of the two kinds of tickets, and the other equation shows the relationship between their values.

Let s be the number of student tickets and n be the number of non-student tickets.

The first thing we know is that s+%2B+n=812 because the problem says 812 tickets were sold.

Since each student ticket costs $2, the total value of the student tickets must be 2s. Likewise, the total value of non-student tickets must be 3n. We are also given that the total value of all the tickets is $1912, so we can write:

2s%2B3n=1912

Take the first equation and solve it for one of the variables, let's solve for n:

s+%2B+n=812
s%2Bn-s=812-s
n=812-s

Now we have an expression for n that can be substituted into the second equation:

cartoon%282s%2B3%2Ared%28n%29=1912%2C2s%2B3%2Ared%28%28812-s%29%29=1912%29

Distribute the 3 and collect like terms:
2s%2B2436-3s=1912
2436-s=1912
-s=1912-2436
-s=-524
s=524

Now we know that 524 student tickets were sold, which is what the question asked.

Check:
If 524 student tickets were sold, then 812+-+524+=+288 non-student tickets were sold.
524%2A2%2B288%2A3=1048%2B864=1912 answer checks.