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Question 122017: The larger of two consecutive intergers is 7 greater than twice the smaller. Find the integers.
The intergers are _____ and _____.
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! IS YOUR PROBLEM ONE OF NOT BEING ABLE TO READ & UNDERSTAND THE PROBLEM OR OR IS IT NOT BEING ABLE TO TRANSLATE THE WORDS INTO A FORMULA.
IF IT IS THE LATER, I SUGGEST YOU TRY REPLACING THE UNKNOWNS WITH ACTUAL NUMBERS/INTEGERS, CONSTRUCT THE EQUATIUON AND THEN REPLACE THE NUIMBERS/DIGITS WITH THE AN UNKNOWN TERM.
I WOULD ALSO SUGGEST YOU MAKE A LIST OF ALL THE FORMULAS/EQUATIONS YOU HAVE LEARNED IN A BOOK FOR REFERENCE WHEN YOU ENCOUNTER A PROBLEM YOU CAN'T FIGURE OUT. MATH IS ONLY A PROBLEM WHEN YOU FORGET THE BASICS. EXCEPT FOR WORD PROBLEMS. THEN YOU HAVE TO THINK THEM THROUGH, DRAW A SKETCH, ASSIGN SOME POTENTIAL VALUES TO AN UNKLNOWN OR SEEK HELP. WHICH IS WHY WE ARE HERE FOR YOU.
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LET X & X+2 BE THE INTEGERS.
(X+2)+7=2X
X+2+7=2X
X-2X==-2-7
-X=-9
X=9 ANSWER FOR THE SMALLER INTEGER.
9+2=11 IS THE LARGER INTEGER.
PROOF.
11+7=2*9
18=18
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