SOLUTION: Someone please help! The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. Any help would be g

Algebra ->  Rectangles -> SOLUTION: Someone please help! The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. Any help would be g      Log On


   

Question 121961: Someone please help! The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. Any help would be greatly appreciated.
Answer by tutor_paul(519) About Me  (Show Source):
You can put this solution on YOUR website!
Let L=length and W=width. You are given:
Equation #1: L=2W%2B8
You are also given:
Equation #2: 2L%2B2W=64
So you have 2 equations and 2 unknowns. Anytime you can form at least as many equations as unknowns, you can solve the problem!
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Substitute the expression for L from Equation #1 into Equation #2:
2%2A%282W%2B8%29%2B2W=64
Solve for W:
4W%2B16%2B2W=64
6W=48
highlight%28W=8%29
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Good Luck,
tutor_paul@yahoo.com