SOLUTION: write the equation of the line with slope 5 and y-intercept (0,-3) thanks for the help

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Question 121925: write the equation of the line with slope 5 and y-intercept (0,-3)
thanks for the help

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of 5 which goes through the point (0,-3), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y--3=%285%29%28x-0%29 Plug in m=5, x%5B1%5D=0, and y%5B1%5D=-3 (these values are given)


y%2B3=%285%29%28x-0%29 Rewrite y--3 as y%2B3


y%2B3=5x%2B%285%29%28-0%29 Distribute 5

y%2B3=5x%2B0 Multiply 5 and -0 to get 0

y=5x%2B0-3 Subtract 3 from both sides to isolate y

y=5x-3 Combine like terms 0 and -3 to get -3
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Answer:


So the equation of the line with a slope of 5 which goes through the point (0,-3) is:

y=5x-3 which is now in y=mx%2Bb form where the slope is m=5 and the y-intercept is b=-3

Notice if we graph the equation y=5x-3 and plot the point (0,-3), we get (note: if you need help with graphing, check out this solver)

Graph of y=5x-3 through the point (0,-3)
and we can see that the point lies on the line. Since we know the equation has a slope of 5 and goes through the point (0,-3), this verifies our answer.